Y=-7.62x^2-5.21x+6.11x=1

Solution for Y=-7.62x^2-5.21x+6.11x=1 equation:

=-7.62Y^2-5.21Y+6.11Y=1

We move all terms to the left:

-(-7.62Y^2-5.21Y+6.11Y)=0

We get rid of parentheses

7.62Y^2+5.21Y-6.11Y=0

We add all the numbers together, and all the variables

7.62Y^2-0.9Y=0

a = 7.62; b = -0.9; c = 0;
Δ = b2-4ac
Δ = -0.92-4·7.62·0
Δ = 0.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.9)-\sqrt{0.81}}{2*7.62}=\frac{0.9-\sqrt{0.81}}{15.24}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.9)+\sqrt{0.81}}{2*7.62}=\frac{0.9+\sqrt{0.81}}{15.24}
$